SOLUTION: a. A=1/3h(a+4b+c) a=2,h=1;c=4;b=0
b. b=a+d(n-1); for d
This is a literal equation solve for the unknown. I am not sure how to solve these equations please help m
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Question 63614This question is from textbook beginning algebra
: a. A=1/3h(a+4b+c) a=2,h=1;c=4;b=0
b. b=a+d(n-1); for d
This is a literal equation solve for the unknown. I am not sure how to solve these equations please help me.
This question is from textbook beginning algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a. A=(1/3)h(a+4b+c) a=2,h=1;c=4;b=0
A=(1/3)(3)(2+0+4)
A=6
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b. b=a+d(n-1); for d
d=(b-a)/(n-1)
---------
Cheers,
Stan H.
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