SOLUTION: I cannot figure out how to solve systems by graphing. I have read and read but am so confused. I need to solve the system 2x+y=2; 6x+4y=12. Please help me figure out the answer

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: I cannot figure out how to solve systems by graphing. I have read and read but am so confused. I need to solve the system 2x+y=2; 6x+4y=12. Please help me figure out the answer       Log On


   



Question 632161: I cannot figure out how to solve systems by graphing. I have read and read but am so confused. I need to solve the system 2x+y=2; 6x+4y=12.
Please help me figure out the answer and show/explain how. Thanks.

Found 2 solutions by josmiceli, ewatrrr:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You have 2 straight lines. The best way to get an
idea what they look like is to convert the equations
from the standard form ( as they now are ) into
the slope-intercept form
---------------------
+2x+%2B+y+=+2+
(1) +y+=+-2x+%2B+2+
and
+6x+%2B+4+y+=+12+
+3x+%2B+2y+=+6+
(2) +2y+=+-3x+%2B+6+
---------------------
(1) and (2) are now in the form +y+=+m%2Ax+%2B+b+
where +m+ = slope and +b+ = y - intercept
---------------------
In (1), +m+=+-2+
In (2), +m+=+-3+
Both slope are negative, which means they go from
upper left to lower right on the graph, opposite to
what a positive slope does
---------------------
+b+ gives you a point for free on each line. It
is the y-intercept point which is (0,b), or
(0, 2) for equation (1)
(0,6) for equation (2)
--------------------
Now you just need 1 other point for both lines, and
since 2 points determine a line, you can draw
each line. Where the lines intersect is the solution
to the system of lines
--------------------
To find the other point, just plug in any value for
+x+, and read off the value for y
For example:
(1) +y+=+-2x+%2B+2+
I'll pick +x+=+1+
(1) +y+=+-2%2A1+%2B+2+
(1) +y+=+0+
So, I have the point (1,0)
and
(2) +2y+=+-3x+%2B+6+
I'll pick +x+=+2+
(2) +2y+=+-3%2A2+%2B+6+
(2) +2y+=+0+
(2) +y+=+0+
So, I have the point (2,0)
---------------------
Now you have this information about the lines:
Line (1):
(0,2)
(1,0)
+m+=+-2+
----------
Line (2):
(0,6)
(2,0)
+m+=+-3+
----------
And that's all you need

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Solve the system by putting each of their graphs on the same graph
the point they intersect at: (-2,6) is the solution for this system

If You are having difficulty graphing each of the linear equations:
find at least 2 (x,y)points for each and connect pair of the 2 points with their
respective line
2x+y=2 x = 0 ⇒ y = 2, y = 0 ⇒ x = 1 (0,2) and (1,0) on this line
6x+4y=12 x = 0 ⇒ y= 3, y = 0 ⇒ x = 2 (0,3) and (2,0) on this line