SOLUTION: Simpliy: This is so complicated please help. 2/z^2

SOLUTION: Simpliy: This is so complicated please help. 2/z^2 - 3/2 / 2/5z^2 + 1/3z

Question 63173: Simpliy: This is so complicated please help.
2/z^2 - 3/2 / 2/5z^2 + 1/3z
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
-
------------
+
:
Get the numerator into a single fraction, common denominator is 2z^2
giving you:
- = =
:
Do the same with the denominator, common denominator 15z^2
+ = =
:
Remember when we divide we invert the dividing fraction and mult so we have:
*
:
We can cancel the z^2 which are in the single terms:
* = = about as far as we can go with it.
:
Could you follow all this? Study each step and it will make sense to you. good luck!
RELATED QUESTIONS
please help me solve: simpliy:... (answered by lwsshak3)

5z+2=z-3 please help me solve this... (answered by jim_thompson5910)

3z^-7+4z^-6+6z^-5+5z^-4+4z^-3+3z^-2+z^-1 (answered by Fombitz)

-(3z+2)-5z-18 (answered by rfer)

Would someone please help me understand this?: -2(z-4)-(3z-2)=-2-(6z-2)... (answered by Earlsdon)

(5z+2)(z^2+3z+2) Please help, I cannot seem to come up with the correct... (answered by umnikmo,rfer,bucky)

-[3z^2+2z-(2z^2-5z)]+[(7z^2-[5z-z^2])+2z^2] (answered by Theo)

Perform the operations. -[3z^2+2z-(2z^2-5z)]+[(7z^2-[5z-z^2])+2z^2] (answered by fractalier)

5z^2 - 5z + 4 - (3z -... (answered by checkley71)