SOLUTION: Solve the system of linear equations and check any solution algebraically. (If there is no solution, enter NO SOLUTION. If the system is dependent, set z = a and solve for x and y

Question 631458: Solve the system of linear equations and check any solution algebraically. (If there is no solution, enter NO SOLUTION. If the system is dependent, set z = a and solve for x and y in terms of a.)
2x + 2z = 2
5x + 3y = 3
3y − 4z = 2
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

3y − 4z = 2   3y = 4z + 2

5x + 3y = 3

5x + 4z = 1

2x + 2z = 2   |multiply 2nd Eq by 2 and subtract for 1st EQ

   x= -3  and  z = 4 

Independent system with one solution (-3,6,4) 

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