# SOLUTION: solve 2x-y+z=-7, x-3y+4z=-19, and -x+4y-3z=18 can someone show how they got the answer please, ty

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 Question 626982: solve 2x-y+z=-7, x-3y+4z=-19, and -x+4y-3z=18 can someone show how they got the answer please, tyFound 2 solutions by ewatrrr, stanbon:Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi, solve by finding the value of 4 matrices 2x- y+ z=-7, x-3y+4z=-19, -x+4y-3z=18 A= |A|= a1(b2c3-c2b3) - b1(a2c3-c2a3) + c1(a2b3-b2a3) = -12 = 12 x = = -24 y = = 36 z = ```Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!solve 2x-y+z=-7 x-3y+4z=-19 -x+4y-3z=18 ---------------- Rearrange the equations x-3y+4z = -19 -x+4y-3z= 18 2x-y+z = -7 ------ Add 1st to 2nd Subtract 2 times 1 from 3rd to get: x - 3y + 4z = -19 0 + y + z = -1 0 + 5y - 7z = 41 -------------------- Subtract 5 times 2nd from 3rd to get: x - 3y + 4z = -19 0 + y + z = -1 0 + 0 - 12z = 36 --------------------- Solve the 3rd equation for "z": z = -3 ----- Substitute z = -3 into the 2nd equation and solve for "y": y = 2 ---- Substitute z = -3 and y = 2 into the 1st equation and solve for "x": x -3*2 + 4*-3 = -19 x -6 -12 = -19 x = -1 ========== Cheers, Stan H. ==========