# SOLUTION: One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture?

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 Question 62496: One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture?Found 4 solutions by checkley71, josmiceli, stanbon, venugopalramana:Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!400*.25=.10X+.35(400-X) 100=.10X+140-.35X .25X=40 X=40/.25 X=160 GALLONS OF 10 % GASOHOL 400-160=240 GALLONS OF 35 % ALCOHOL PROOF 400*.25=.10*160+.35*240 100=16+84 100=100 Answer by josmiceli(9671)   (Show Source): You can put this solution on YOUR website!a = gasohol 10% alcohol b = gasohol 35% alcohol multiply 2nd equation by .1 subtract 2nd from 1st 240 gal of the .1 mixture and 160 gal of the .35 misture Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!One type of gasohol is 10% alcohol and another type is 35% alcohol. How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? ------------- Let amount of 10% solution be "x" gallons; this has 0.10x gals. of alcohol ---------- Amount of 35% solution is "400-x" gallons; this has 0.35(400-x)=140-0.35x gals ------------------ EQUATION: alcohol + alcohol = 25%(400) gallons 0.10x+140-0.35x=100 -0.25x=-40 x=160 gallons (amount of 10% solution) 400-x=240 gallons (amount of 35% solution) Cheers, Stan H. Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!One type of gasohol is 10% alcohol( T SAY) and another type is 35% alcohol(F SAY). How much of each type must be mixed to obtain 400 gallons of a 25% alcohol mixture? T+F = 400 G......F = 400 - T G....................1 ALCOHOL IN T = T*10/100=0.1T G.....................2 ALCOHOL IN F = F*35/100=0.35F=0.35(400-T)=140-0.35T G.............3 TOTAL ALCOHOL IN THE MIX = 400*25/100=100 G.................4 HENCE 0.1T+140-0.35T=100 0.35T-0.1T=140-100=40 0.25T = 40 T=40/0.25=160 G............IS 10% ALCOHOL IN THE MIX F=400-160=240 G............IS 35% ALCOHOL IN THE MIX