Hi,

parabola: with axis of symmetry x = 3, passing thru (0,10) and (2,0)

y = a(x-h)^2 + k  

|Note: Parabola with this format.. always opens along its axis of symmetry x = h

y = a(x-3)^2 + k   Pt(2,0)

0 = a(-1)^2 + k

-k = a

10 = a(-3)^2 + k     Pt(0,10)

(10-k)/9 = a

(10-k)/9 = -k

  10-k = -9k

    8k = -10

     k = -10/8 = -5/4  and a = 5/4

  

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