SOLUTION: This chap is asking to solve the system of equation using subsititution method but I keep getting the wrong ans.
9. 2x+y=5
x+3y=0 the book ans is (3,-1)
11. 2x+y=3
Algebra.Com
Question 62125This question is from textbook beginning algebra
: This chap is asking to solve the system of equation using subsititution method but I keep getting the wrong ans.
9. 2x+y=5
x+3y=0 the book ans is (3,-1)
11. 2x+y=3
2y=-4x+6 the book ans is (Many solutions)
13. x-y=3
3y=x the book ans is (9/2,3/2)
15. 2x+y=-4
x-2y=-7 the book ans is (-3,2)
17. 4x+y=5
x-3=0
I am having problem solving using the substitution method. PLEASE HELP ME!
This question is from textbook beginning algebra
Found 2 solutions by checkley71, Earlsdon:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
I'LL SOLVE THE FIRST ONE & LEAVE THE REST FOR YOU
2X+Y=5
X+3Y=0 SOLVING THIS EQUATION FOR X WE GET
X=-3Y NOW SUBSTITUTE (-3Y) FOR X IN THE FIRST EQUATION
2(-3Y)+Y=5
-6Y+Y=5
-5Y=5
Y=5/-5
Y=-1 SOLUTION NOW SUBSTITUTE (-1) SECOND EQUATION
X+3(-1)=0
X-3=0
X=3 SOLUTION
NOW SUBSTITUTE BOTH VALUES (-1 FOR Y & 3 FOR X) THIS IS THE PROOF
2+3*-1=5
6-1=5
5=5 &
3+3*-1=0
3-3=0
0=0
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve by substitution:
(9)
Rewrite this as: and substitute for x in the 1st equation.
Solve for y.
To find x, use:
Solution is: (3, -1)
(11)
Rewrite as: and substitute for y in the 2nd equation.
Simplify and solve for y.
Add 4x to both sides.
The two equations represent the same line so there are an infinite number of solutions.
(13)
Substitute this for x in the 1st equation and solve for y.
Substitute
Solution is: (9/2, 3/2)
(15)
Rewrite this as: and substitute for x in the 1st equation.
Simplify and solve for y.
Substitute and solve for x.
The solution is: (-3, 2)
(17)
Rewrite this as: and substitute for x in the 1st equation and solve for y.
The solution is: (3, -7)
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