SOLUTION: the perimeter of a rectangle is 82 yards. The width is 15 yards less than the length. Find the lenght and the width of the rectangle.
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Question 61975: the perimeter of a rectangle is 82 yards. The width is 15 yards less than the length. Find the lenght and the width of the rectangle.
Answer by 303795(602) (Show Source): You can put this solution on YOUR website!
Call the length of the rectangle l. the width is 15 yards less than the length so the width is l - 15.
The perimeter of the rectangle = length + length + width + width
Using the length (l) and width (l - 15) then the perimeter can be found by
Perimeter = l + l + l -15 + l - 15 = 4l - 30
This equals 82 yards so
4l - 30 = 82 Add 30 to each side of the equation
4l = 82+30 = 112
4l = 112 Divide each side of the equation by 4
l = 112 / 4 = 28 Yards
The width is 15 less than this ie 28 - 15 = 13 Yards
(Be careful with the letter l which I have used in the example. It can look like a number one.)
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