SOLUTION: The sum of two consecutive positive intergers is less than 92. Find the pair with the greatest sum.

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Question 61953: The sum of two consecutive positive intergers is less than 92. Find the pair with the greatest sum.
Found 3 solutions by checkley71, stanbon, joyofmath:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X+(X+2)<92
2X+2<92
2X<92-2
X<90/2
X<45

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of two consecutive positive intergers is less than 92. Find the pair with the greatest sum.
Let the numbers be x and x+1
EQUATION:
x+x+1<92
2x+1<92
2x<91
If x is an integer 2x cannot be an odd number,
i.e. 2x cannot be 91.
So it must be 90 if the numbers are to have the greatest sum.
2x=90
x=45
x+1=46
The greatest sum is 91.
Cheers,
Stan H.

Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!
x%2B%28x%2B1%29+%3C+92.
2x%2B1+%3C+92.
2x+%3C+91.
x+%3C+45.5.


x is an integer < 45.5 so x = 45.


So, the pair of numbers is 45 and 46.