# SOLUTION: A tugboat goes 120 miles upstream in 20 hrs. the return trip downstream takes 5 hrs. find the speed of the tugboat without a current and the speed of the current The speed of the

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: A tugboat goes 120 miles upstream in 20 hrs. the return trip downstream takes 5 hrs. find the speed of the tugboat without a current and the speed of the current The speed of the      Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Question 618025: A tugboat goes 120 miles upstream in 20 hrs. the return trip downstream takes 5 hrs. find the speed of the tugboat without a current and the speed of the current The speed of the tugboat is The speed of the current is simplify your answersAnswer by ankor@dixie-net.com(15646)   (Show Source): You can put this solution on YOUR website!): A tugboat goes 120 miles upstream in 20 hrs. the return trip downstream takes 5 hrs. find the speed of the tugboat without a current and the speed of the current : Let s = boat speed in still water Let c = speed of the current then (s-c) = effective speed upstream and (s+c) = effective speed downstream : Write distance equation for each way. (dist = time * speed 20(s-c) = 120 5(s+c) = 120 Simplify both equations, divide the 1st equation by 20, divide the 2nd equation by 5, results: s - c = 6 s + c = 24 -----------Adding eliminates c find s 2s = 30 s = 30/2 s = 15 mph boat speed in still water : You can find the current, check the solutions in the original equations :