# SOLUTION: Joe has been collecting dimes and quarters all year. Now he wants to buy a present for his wife, so he opens his piggy bank. He has 479 coins. When the bank puts them through its

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: Joe has been collecting dimes and quarters all year. Now he wants to buy a present for his wife, so he opens his piggy bank. He has 479 coins. When the bank puts them through its      Log On

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 Question 60618: Joe has been collecting dimes and quarters all year. Now he wants to buy a present for his wife, so he opens his piggy bank. He has 479 coins. When the bank puts them through its counting machine, it tells him he has \$72.50. How many dimes and how many quarters does he have? Answer by uma(370)   (Show Source): You can put this solution on YOUR website!Let Joe have x dimes and y quarters. Then x + y = 479 ---------(1) [since he had 479 coins] Value of x dimes = 10x cents Value of y quarters = 25y cents Total value = 10x + 25y ==> 10x + 25y = 7250 cents [he totally had \$72.50] ==> 10x + 25y = 7250 ------------------(2) Multiplying (1) by 10 we get.. 10x + 10y = 4790 10x + 25y = 7250 --------(2) Subtracting the above two equations, we get - 15y = -2460 ==> -15y/-15 = -2460/-15 ==> y = 164 Plugging in this value in (1) , x + 164 = 479 ==> x = 479 - 164 [Subtracting 164 from both the sides ] ==> x = 315 So Joe had 315 dimes and 164 quarters.