SOLUTION: Solve the following equations...this is what i did 1) 4x/x+2 + 3/x-2=4 when i set it up this is what i got 4x(x-2)+3(x+2)=4(x+2)(x-2) 2.)10b-50/b^2-b-20 divided by 15/

Question 596016: Solve the following equations...this is what i did
1) 4x/x+2 + 3/x-2=4
when i set it up this is what i got
4x(x-2)+3(x+2)=4(x+2)(x-2)
2.)10b-50/b^2-b-20 divided by 15/6b+24
answer: i factored everything and flipped it over since it says to divide and i got
10(b-5)/(b+4)(b-5) X 6(b+4)/15
10(b-5)/15(b-5) where should the 6 go?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
# 1

You're on the right track. Now foil/expand, simplify and get into standard form

The x squared terms cancel and we're left with a linear equation. I'll let you solve this. Tell me what you get.

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# 2

The 6 is in the numerator of the second fraction (in step 2).

So it should stay in the numerator. You can multiply it with the 10 in the numerator of the first fraction to get 10*6 = 60

So you'll end up with

60(b-5)/15(b-5)

which can be simplified further (I'll let you take over from here. Let me know what you get)

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