SOLUTION: A father is 30 years older than his son, one year ago he was 4 times as old as his son, find their present ages?
Algebra.Com
Question 584702: A father is 30 years older than his son, one year ago he was 4 times as old as his son, find their present ages?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
son age =x
father -age = x+30
last years
son - age = x-1
father-age = (x+30)-1= x+29
(x+29)= 4(x-1)
x+29 = 4x-4
4x-x= 29+4
3x=33
/3
x= 11 years son's age
father's age = 30+11= 41 years
RELATED QUESTIONS
a father is 30 years older than his son..a year ago he is 4 tyms as old as his son find... (answered by macston)
mr.jones is 30 years older than his son. six years ago he was 7 times as old as his son... (answered by lwsshak3)
A father is twice as old as his son, 12 years ago,the father was 4 times older as his... (answered by richwmiller)
A father is now 3 times older than his son.12 years ago he was 6 times as old as his... (answered by josmiceli)
Plz answer me quick.....
A father is 30years older than his son and one year ago he was... (answered by josgarithmetic)
a father is 20years older than his son 12years ago he was sixtimes as old as his son find (answered by Alan3354)
A man is 3 times as old as his son. 5 years ago, he was 4 times as old as his son. Find... (answered by stanbon,Vixiachase)
a father is 30 years older than his son. in 12 years, the father will be twice as old as... (answered by Maths68)
a father is 30 years older than his son. three years ago he was four times as old as his... (answered by richwmiller)