SOLUTION: I need help with this (solving systems). The Science Club needs to rent a bus for a field tripe. M.S. Buses charges a $40 rental fee, plus $2 per mile. C.B. Buses charges a $20

Question 567653: I need help with this (solving systems).
The Science Club needs to rent a bus for a field tripe. M.S. Buses charges a $40 rental fee, plus $2 per mile. C.B. Buses charges a $20 rental fee, plus $3 per mile. For what number of miles will the total be the same? What will the charge be?
How would I solve this problem? Thank you for the help.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The Science Club needs to rent a bus for a field tripe. M.S. Buses charges a $40 rental fee, plus $2 per mile. C.B. Buses charges a $20 rental fee, plus $3 per mile. For what number of miles will the total be the same? What will the charge be?
How would I solve this problem?
Write a cost equation for each statement and make them equal to each other
:
Let m = no, of miles for this to be true
:
" M.S. Buses charges a $40 rental fee, plus $2 per mile.
C = 2m + 40
:
"C.B. Buses charges a $20 rental fee, plus $3 per mile."
C = 3m + 20
:
3m + 20 = 2m + 40
now just solve for m, then find the cost by replacing m with that value in both equations.
If you did it right, they should be equal.
;
Let me know if you have difficulty with this.
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