SOLUTION: I tried to use every system to solve these problems... I have an "a" and a "b" in each problem
A: x+5y = -15
y = 1/5x + 1
[ I got (-8, -1.2)for my answer]
B:
Algebra.Com
Question 566186: I tried to use every system to solve these problems... I have an "a" and a "b" in each problem
A: x+5y = -15
y = 1/5x + 1
[ I got (-8, -1.2)for my answer]
B: 2x - 3y = -27
-3x + 2y = 23
[ I got -3 for my answer]
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This one is set up for Substitution, but can easily be done by Elimination.
Substitution solution:
The second equation defines 
in terms of 
, so substitute the RHS expression from the second equation in place of in the first equation:
\ =\ -15)
Solve for , then substitute the value back into either original equation (I suggest the second one since it gives you directly) and solve for
Elimination solution:
The first equation is already in Standard Form, i.e. 
where A, B, and C are integers. Put the second equation into Standard Form.
Now add the two equations, term by term which will eliminate the variable, leaving you with a single equation in . Solve that and substitute back.
John
My calculator said it, I believe it, that settles it
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