SOLUTION: find the equation of a line whose intercepts are twice of the line 3x-2y-12=0

Question 553677: find the equation of a line whose intercepts are twice of the line 3x-2y-12=0

Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
3x-2y-12=0
2y=3x-12
/2
y=(3/2)x-6
Y intercept plug x=0
y=-6
(0,-6)
X intercept pluf y=0
3/2x = 6
3x=12
/3
x=4
(4,0)
The intercepts are twice

y intercept = (0,-12)
X intercept =(8,0)
The slope will be the same = 3/2 and passes through (8,0)
m= 3/ 2

Plug value of the slope and point (0,8) in
Y = m x + b
0 = 3/2 *8 + b
b= 12 - 0
b= -12
So the equation will be
Y = 3/2 x -12

m.ananth@hotmail.ca

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