# SOLUTION: I Am really struggling on solving linear equations with substitution and elimination. could you help me out and tell me the most easiest way to do these

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 Click here to see ALL problems on Linear-systems Question 538697: I Am really struggling on solving linear equations with substitution and elimination. could you help me out and tell me the most easiest way to do theseAnswer by JLB(8)   (Show Source): You can put this solution on YOUR website!This is an example of a linear equation : 2x + 4 = 10 2x + 4 = 10 The goal is to find what X is equal to, your final answer is X = (answer) The first step in solving this equation is to subtract 4 from both sides. (Remember that what you do to one side you must do to both sides). 2x + 4 - 4 = 10 - 4 2x = 6 Now you just need to divide both sides by 2, and you will get the final answer: x = 3 Let's do another one. Do you see that? You need to do the opposite operation (subtracting and adding are opposite, division and multiplication are opposite) to both sides. So when you see x - 1 = 12, you know to add 1 to 12 to get 13, and to cancel out the x + 1 to get simply x. x = 13.