SOLUTION: linear algebra elimination method 13) 2/3x+2/5y=4/5 1/2x+2/3y=-1/2 12)9/14x+y=19/7 -20x+21y=144 11)x+5/3y=7/3 2/5x-y=3/5 10)x+9/4y=7/4 5/9x-y=2/9 8)18x

Algebra.Com
Question 528396: linear algebra elimination method
13) 2/3x+2/5y=4/5
1/2x+2/3y=-1/2
12)9/14x+y=19/7
-20x+21y=144
11)x+5/3y=7/3
2/5x-y=3/5
10)x+9/4y=7/4
5/9x-y=2/9
8)18x-3y=-3
6x+7y=39
6)15x+14y=2
12x-6y=-7

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
I'll just do this one: 

 x + y = 
 -20x + 21y = 144

To clear the first one of fractions multiply 
every term by the LCD of 14:

14·x + 14·y = 14·
  
9x + 14y = 38

Now we have the system:

  9x + 14y =  38
-20x + 21y = 144

The idea is to eliminate a variable:
The coefficients of y are 14 and 21
The least common multiple of 14 and 21
is 42.  To make the coefficients of
y equal in absolute value yet opposite
in sign we multiply the first equation
through by -3 and the second equation
through by 2.  That will make the
coefficients -42 and +42:

-3[  9x + 14y] = -3[38]
 2[-20x + 21y] =  2[144]

   -27x - 42y = -114
   -40x + 42y =  288

Now we add those term by term:

   -27x - 42y = -114
   -40x + 42y =  288
  -------------------
   -67x       =  174
      x       =  

Since that is too complicated a fraction to
substitute, we will start over and eliminate x:

---------------------------
       
  9x + 14y =  38
-20x + 21y = 144

Next we eliminate the other variable x:
The coefficients of x are 9 and -20
The least common multiple of 9 and 20
is 180.  To make the coefficients of
x equal in absolute value yet opposite
in sign we multiply the first equation
through by 20 and the second equation
through by 9.  That will make the
coefficients +180 and -180:

20[  9x + 14y] = 20[38]
 9[-20x + 21y] =  9[144]

   180x + 280y =  760
  -180x + 189y = 1296

Now we add those term by term:

   180x + 280y =  760
  -180x + 189y = 1296
  -------------------
          469y = 2056
             y = 

-------------

So the solution is 

Edwin

RELATED QUESTIONS

Solve by elimination: 1.8x + 11y= 20 5x - 11y= -59 2. 2x + 18y= -9 4x + 18y= -27 (answered by jim_thompson5910)
1. 4x+3y=1, x=1-y 2. 2x-y=6, -x+y=-1 3. 6x-y=3, 4x-2y=-2 4. 2x+3y=7, x=1-4y 5.... (answered by AnlytcPhil)
What is the solution to 1. y = 3x – 8 y = 4 – x 2. x + y = 0 3x + y = -8 (answered by Alan3354)
I am solving by using the elimination method. -5x+y=-13 6x-5y=8 5x=8+3y 3x-4y=18 (answered by MathLover1)
CRAMER RULE, ELIMIATION OR SUBSTITUTION METHOD, AND MATRICES PRACTICE PROBLEMS 1. (answered by richard1234)
How would I solve these systems? 1)x+5y=4 3x-7y=-10 2)-5x+3y=6 x-y=4 (answered by elima)
Solve each system of equations by the substitution method. 1) y=3x 5x+2y=44... (answered by solver91311,Alan3354)
SOLVE STEP BY STEP THANK YOU:) 1) x+y=5 3x-y=7 2) 2x+y=3 -2x+5y=-9 3) 3x+5y=0 (answered by Alan3354)
Solve the system using the substitution method. Show all your steps. 1. x+2y=6... (answered by checkley79)