SOLUTION: 2.00x+1.5y=550.00 x=3y-100 i need to graph so im guessing it needs to be in slope intercept form? i keep getting decimals and i need help

Algebra.Com
Question 521829: 2.00x+1.5y=550.00
x=3y-100
i need to graph so im guessing it needs to be in slope intercept form? i keep getting decimals and i need help

Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
2.00x + 1.5y = 550.00
multiply by 10 to eliminate decimals
20x + 15y = 5500
15y = -20x + 5500
y = -(20/15)*x + 5500/15
y = -(4/3)x + 1100/3
.
x = 3y -100
x + 100 = 3y
3y = x + 100
y = x/3 + 100/3
.

.
To eliminate fractions, you need to multiply by 3. That could be rearranged into standard form.
.
3y = -4x + 1100
4x + 3y = 1100
.
y = x/3 + 100/3
3y = x + 100
-x + 3y = 100
.
This layout suggests a set of linear equations:
.
4x + 3y = 1100
-x + 3y = 100
---------------
5x = 1000
x = 200
.
Substitute x = 200
.
-200 +3y = 100
3y = 300
y = 100
.
So, the lines intersect at (200,100).
.
You can check using the other equation:
4(200) + 3(100) = 1100
True
.
Done.

RELATED QUESTIONS

I need to graph the equation 5x-2y=4, and I'm guessing I need to convert it to... (answered by checkley77)
Need to make sure my calculation is correct. need to take x+2y=8 into slope intercept... (answered by josgarithmetic)
2x+y≤2 I need you to convert it to slope-intercept form. The assignment gave me a... (answered by Boreal,MathLover1)
ok so im working with slopes and i just keep getting everything confused and im going a... (answered by Alan3354)
Write the equation in slope-intercept form of the line passing through the point(-3,-1)... (answered by texttutoring)
How am I supposed to write this in slope- intercept form and graph it {{{ 5y=9x }}} (answered by solver91311)
I need to put 2x+y=4 in slope-intercept form and graph it (answered by ikleyn,Alan3354)
Hi I have worked this problem and now need to know if I did it right so that I can graph... (answered by jim_thompson5910)
Im not sure how to do this I keep getting a decimal but It shows to be a fraction?... (answered by fractalier)