SOLUTION: tried to use the linear system solver and cannot figure it out. Keeps telling me there is an error. Please help solve the system by substitution. 4x-12y=5 -x+3y=-1

Question 50183This question is from textbook Beginning Algebra
: tried to use the linear system solver and cannot figure it out. Keeps telling me there is an error.
Please help solve the system by substitution.
4x-12y=5
-x+3y=-1 This question is from textbook Beginning Algebra

Answer by junior403(76) (Show Source): You can put this solution on YOUR website!
Solve the system by substitution.
4x -12y = 5
-x + 3y = -1
First we need to figure our which equation we want to use as the substitution and solve for one of the variables.
-x + 3y = -1 seems like the best choice since the x variable has the coefficieant of 1. So lets solve for x in order to isolate the variable.
-x + 3y = -1
lets subtract 3y from both sides to isolate the x.
so...
-x = -3y - 1
now we can distribute out the - sign to make it easier.
x = 3y +1
now we simply substitute our new equation for the variable x in the secound equation 4x - 12y = 5
4(3y +1) -12y = 5
Now we can just solve.
4(3y +1) -12y = 5
12y +4 -12y = 5
4 = 5
is this possible?
No.
so our solution 0 or empty set { }.
I hope this helps.
Good Luck!

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