SOLUTION: can someone please help me solve the following equations for x 1) 6/x+3=9x/x^2-9 2) sqrt2x+3=5 3) x^3-2x^2-x=2 given x=1 is one solution. Thank you

Question 483274: can someone please help me solve the following equations for x
1) 6/x+3=9x/x^2-9
2) sqrt2x+3=5
3) x^3-2x^2-x=2 given x=1 is one solution.
Thank you

Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
1) We write the equation in the simple way to find the LCD:
.Assuming x different from 3 and -3, multiply both
sides by (x+3)(x-3) and get:<=><=>.
2) Squaring both sides we get:2x+3=25<=>2x=22<=>x=11.
3)Since x=1 is a solution the polynomial is divisible by x-1
<=>
To find the other roots we solve the quadratic equation:
<=>. The solution set for the original equation
is:{-1, 1, 2}.
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