SOLUTION: We were told to solve these systems by graphing but, on the graph he has a place for six points it is mapped out as: x y1 y2 0 0 0 0 0 0 My first problem is x + 2y = 4

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: We were told to solve these systems by graphing but, on the graph he has a place for six points it is mapped out as: x y1 y2 0 0 0 0 0 0 My first problem is x + 2y = 4       Log On

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Question 48127: We were told to solve these systems by graphing but, on the graph he has a place for six points it is mapped out as:
x y1 y2
0 0 0
0 0 0
My first problem is x + 2y = 4
x + 2y = -2
My solutions were x = (0,2) (4,0)
y = (-4,1)(0.-4)
How do i graph this where do I place the numbers on the graph.
Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
Before doing any substitutions, always solve for y. Doing so yields y=-expr%281%2F2%29x%2B2 and y=-expr%281%2F2%29x-1. Because the slopes are exactly the same, that means the lines are parallel. If you substitute 0 for x in both equations you get y=2 for the first equation and y=-1 for the second equation. The graph is:
graph%28200%2C200%2C-5%2C5%2C-5%2C5%2C-x%2F2%2B2%2C-x%2F2-1%29