# SOLUTION: can you help me answer 8-5r over 6=3, -4a-1 over -10a=3/8, and y+4 over y-1=4/3 -than

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 Click here to see ALL problems on Linear-systems Question 476706: can you help me answer 8-5r over 6=3, -4a-1 over -10a=3/8, and y+4 over y-1=4/3 -thanksAnswer by stanbon(57407)   (Show Source): You can put this solution on YOUR website!8-5r over 6=3, (8-5r)/6 = 3 (8-5r) = 18 -5r = 10 r = -2 ------------------------- -4a-1 over -10a=3/8, (-4a-1)/10a = (3/8) Cross-multiply: -32a - 8 = -30a 2a = -8 a = -4 ========================= y+4 over y-1=4/3 --- (y+4)/(y-1) = 4/3 --- 3y+12 = 4y-4 y = 16 ----------------- Cheers, Stan H.