-2x-5y-1z=57 -5y-2z=54 -5z=35 That is in echelon (or triangular) form. You start at the bottom and work your way to the top. Start by solving the bottom equation first: -5z=35 z=-7 Now substitute z=-7 in the middle equation: -5y-2z=54 -5y-2(-7)=54 -5y+14=54 -5y=40 y=-8 Now substitute z=-7 and y=-8 in the top equation: -2x-5y-z=57 -2x-5(-8)-(-7)=57 -2x+40+7=57 -2x+47=57 -2x=10 x=-5 (x,y,z) = (-5,-8,-7) Edwin
Solve this system of equations. 3y - z = -1 x + 5y - z = -4 -3x +(answered by Edwin McCravy)
solve the system analytically: x + y + z = 10 2x + 6y + 2z = 40 -x + 7y -...(answered by Edwin McCravy)