SOLUTION: rental car costs $25 per day plus $0.20 per mile. If someone has $200 to spend and needs to drive the car 90 miles each day, for how many days can that person rent the car?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: rental car costs $25 per day plus $0.20 per mile. If someone has $200 to spend and needs to drive the car 90 miles each day, for how many days can that person rent the car?      Log On


   



Question 471094: rental car costs $25 per day plus
$0.20 per mile. If someone has $200 to spend and
needs to drive the car 90 miles each day, for how
many days can that person rent the car?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = number of days the person can rent the car
The formula to use is:
(cost of the rental) = (cost per day)x(number of days) + (cost per mile)x(number of miles)
and
(number of miles) = (miles per day)x(number of days)
given:
Cost per day = 25 dollars/day
Cost per mile = +.02+ dollars/mi
Miles per day = +90+ mi/day
The formula must be OK dimensionally, that is
it must be dollars = dollars
----------------------------
+200+=+25%2Ad+%2B+.02%2A90%2Ad+
+200+=+25d+%2B+1.8d+
+200+=+d%2A%2825+%2B+1.8%29+
+26.8d+=+200+
+d+=+7.463+
The fraction of a day would not be allowed, so
the person could rent the car for 7 days
That means
+25%2A7+%2B+.02%2A90%2A7+
+175+%2B+12.6+
+187.6+
They would spend $187.60