SOLUTION: 1/x+1/y=8/15 1/x-1/y=2/15 solve the system I keep getting x=1/3 and y=1/30

Question 463611: 1/x+1/y=8/15
1/x-1/y=2/15
solve the system
I keep getting x=1/3 and y=1/30
Found 2 solutions by graphmatics, Gogonati:
Answer by graphmatics(170) (Show Source): You can put this solution on YOUR website!
1/x+1/y=8/15
1/x-1/y=2/15
We will first solve the system for x. First we multiply the first equation by y and get
1/x = 8/15 -1/y
1/x = (8/15)(y/y) -(1/y)(15/15)
1/x = (8y/15y) - (15/15y)
1/x = (8y-15)/(15y)
Now substitute the value of 1/x into equation 2 and get
(8y-15)/(15y) - 1/y = 2/15
Multiply this equation by y and get
y(8y-15)/15y - y(1/y) = y(2/15)
(8y-15)/15 - 1 = 2y/15
8y/15 - 15/15 -1 - 2y/15 =0
8y/15 - 2y/15 = 2
6y/15 = 2
y = (15/6)2
y = 15/3 = 5
Substitute y = 5 into the first equation and solve the first equation for x.
1/x = 8/15 - 1/y
1/x = 8/15 - 1/5
1/x = 8/15 - 3/15
1/x = 5/15
1/x = 1/3
x = 3

Answer by Gogonati(855) (Show Source): You can put this solution on YOUR website!
Just add them together and get: => .Plugging x=3 in the
first equation we get: => =>.
The solution is the ordered pair (3, 5).
RELATED QUESTIONS
Use the equation and type the ordered-pairs. 1) y=3^x 2) y = 10^x 3) y=(1/2)^x (answered by richard1234)
solve the system x+y=3 and... (answered by solver91311)
Solve the system x^2 + y = 3 x + y =... (answered by davethejackal)
It says to solve the system of equations using the substitution method. x+y=1 3x+4y=1 (answered by elima)
Solve the system y = x^2 - 4x - 15 y = 2x -... (answered by ankor@dixie-net.com)
Solve the system : y = x^2 + 1 y = 4x + 1 (answered by checkley71)
solve the simultaneous equation : 5/(x+y) - 2/ (x-y) = -1 and 15/(x+Y) + x/(x-y)... (answered by aulii)
Solve for y: y + 1/2 = -1/3 (x + 1/2) What I have done: y + 1/2 = -1/3x + 1/2 *... (answered by MathLover1,checkley71)
Solve the folowing system. x - y = 1 x + y =... (answered by funmath)