# SOLUTION: x + 3y = 32 -3x + 2y = 3 When I try to solve for either x or y variable i get a fraction and/or mixed number and I cant solve it. Thank you for your help Chris

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: x + 3y = 32 -3x + 2y = 3 When I try to solve for either x or y variable i get a fraction and/or mixed number and I cant solve it. Thank you for your help Chris      Log On

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 Click here to see ALL problems on Linear-systems Question 460643: x + 3y = 32 -3x + 2y = 3 When I try to solve for either x or y variable i get a fraction and/or mixed number and I cant solve it. Thank you for your help ChrisAnswer by sudhanshu_kmr(1152)   (Show Source): You can put this solution on YOUR website!x + 3y = 32 -3x + 2y = 3 multiply first equation by 3 and add to second equation you will get, 11y = 99 => y = 9 put this value of first equation, x + 27 = 32 => x = 32-27 = 5 so, x= 5, y = 9 Everyone is welcome to get free online help: sudhanshu.cochin@gmail.com