# SOLUTION: 2x-y+z=10 4x+2y-3z=10 x-3y+2z=8 solve for x, y,z i have so far 2x-y+z=10 4x+2y-3z=10 multiply the first equation by 2 which gives 4x-2y+2z=20 am i

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: 2x-y+z=10 4x+2y-3z=10 x-3y+2z=8 solve for x, y,z i have so far 2x-y+z=10 4x+2y-3z=10 multiply the first equation by 2 which gives 4x-2y+2z=20 am i       Log On

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 Click here to see ALL problems on Linear-systems Question 44821: 2x-y+z=10 4x+2y-3z=10 x-3y+2z=8 solve for x, y,z i have so far 2x-y+z=10 4x+2y-3z=10 multiply the first equation by 2 which gives 4x-2y+2z=20 am i on the right trackAnswer by stanbon(57979)   (Show Source): You can put this solution on YOUR website!Yes, then subtract it from the 2nd equation to eliminate the x-terms. Cheers, Stan H.