SOLUTION: Factor completely.
125a^3 – 27b^3
A) (125a - 3b)(a2 + 15ab + 9b2)
B) (5a + 3b2)(25a2 – 15ab + 9b2)
C) (5a - 3b)(25a2 + 9b2)
D) (5a - 3b)(25a2 + 15ab + 9b2)
E) none of the a
Algebra.Com
Question 445057: Factor completely.
125a^3 – 27b^3
A) (125a - 3b)(a2 + 15ab + 9b2)
B) (5a + 3b2)(25a2 – 15ab + 9b2)
C) (5a - 3b)(25a2 + 9b2)
D) (5a - 3b)(25a2 + 15ab + 9b2)
E) none of the above
I think its C, but I know it can be factored more because 25 can be 5 and 9 can be 3. I just want to make sure its either C or E.
thanks
PAola
Answer by rwm(914) (Show Source): You can put this solution on YOUR website!
D (5a-3b) (25a^2+15ab+9b^2)
RELATED QUESTIONS
Can someone check my answer??
15ab+6ab^4+24ab^3
----------------- =... (answered by ikleyn)
a-b-3b+5a (answered by ikleyn)
4a2+12ab+9b2 (answered by MathLover1)
Factor Polynomial completely.... (answered by Mathtut)
Factor completely:
5ax-5a+3bx-3b
(answered by checkley77)
i need help factoring
18a^2b^2+12a^3b-15ab^3
thank... (answered by Mathtut)
How do I solve this:
example- 12a^3b+15ab^3=3ab(4a^2+5b^2)
*This is called the... (answered by stanbon)
5a(a+3b)+4(a+3b) (answered by nyc_function)
6a-3b+2(b+5a) (answered by fractalier)