For this problem i just need to know the last equation.
A minor league baseball park has 7000 seats. Box seats cost $6,grandstand seats cost $4, and bleachers seats cost $2. When all seats are sold, the revenue is $26400. If the number of box seats is one-third the number of bleachers seats, how many seats of each type are there?
My 2 equations are
x + y + z = 7000
6x + 4y +2z = 26400
What is the last equation?
It comes from this sentence:
"the number of box seats, x, is one-third the number
of bleachers seats, z"
That says:
x is one-third of z
or
x = ⅓z
and then you can clear of fractions by multiplying
both sides by 3 and getting
3x = z
And you could rearrange it as
3x - z = 0
Then your system is
x + y + z = 7000
6x + 4y +2z = 26400
3x - z = 0
answer: x = 400, y = 5400, z = 1200
Edwin