SOLUTION: Please help me to find the solution set(s) to this problem using Addition Method. Thank you.
{{{x^2+y^2=49}}}
{{{y^2-4x=49}}}
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Question 434221: Please help me to find the solution set(s) to this problem using Addition Method. Thank you.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Rearrange it to
Multiply the 2nd eq by -1
------------------addition method eliminates y^2, we are left with:
x^2 + 4x = 0
Factor out x
x(x+4) = 0
Two solutions
x = 0
x + 4 = 0
x = -4
:
It's obvious that x = 0 will work, find y when x = -4
Replace x with - 4 in the 2nd original equation
-4(-4) + y^2 = 49
16 + y^2 = 49
y^2 = 49-16
y^2 = 33
y =
:
You can check the solutions in the 1st original equation
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