SOLUTION: how do i solve 2x-3y=-25
3x+y=1 by substitution
Algebra.Com
Question 424571: how do i solve 2x-3y=-25
3x+y=1 by substitution
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve 2x-3y=-25
3x+y=1 by substitution
------
Here's one way:
y = (2x+25)/3
y = (1-3x)
-----
Substitute y for y:
1-3x = (2x+25)/3
3-9x = 2x+25
11x = -22
x = -2
----
Solve for "y":
y = 1-3x
y = 1-3*-2
y = 7
==================
Cheers,
Stan H.
================
RELATED QUESTIONS
I don't really understand how to do the substitution method.
How would you answer... (answered by jim_thompson5910)
how do i solve by substitution?
2x+3y=6... (answered by jim_thompson5910)
How do I solve by substitution?
2x+y=5... (answered by Alan3354)
Solve by substitution method
3x-y=1
2x-3y=10
(answered by algebrahouse.com)
how do i solve this system by substitution method.
2x-5y=-1... (answered by ewatrrr)
how do I solve this system by using the substitution method?
x + 3y = -1
y =... (answered by TimothyLamb)
how do I solve x+3y=6 and 2x+3y=18 by the substitution... (answered by TimothyLamb,MathTherapy)
How do I solve this problem by substitution?
2x+y=0... (answered by Alan3354)
How do you solve 2x+3y=1 and -3x+y=15 by substitution?
I have tried solving for the x... (answered by MathLover1)