SOLUTION: a chemist has one solution containing 30% insecticide and another solution containing 50% insecticide. How much of each solution should the chemist mix to get 200L of a 42% insecti

Algebra.Com
Question 419086: a chemist has one solution containing 30% insecticide and another solution containing 50% insecticide. How much of each solution should the chemist mix to get 200L of a 42% insecticide?
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
30 ---------------- x
50 ---------------- 200-x
42.00% ---------------- 200
...............
30x+50( 200-x)=42*200
30x+10000-50x=8400
30x-50x =8400-10000
-20x=-1600
/20
x=80 liters 30%
50% ----120 liters

RELATED QUESTIONS

A solution containing 30% insecticide is to be mixed with a solution containing 50%... (answered by fractalier)
A solution containing 30% insecticide is to be mixed with a solution containing 50%... (answered by CharlesG2)
A solution containing 30% insecticide is to be mixed with a solution containing 50%... (answered by checkley77)
A solution containing 30% insecticide is to be mixed with a solution containing 50%... (answered by ptaylor)
A solution containing 30% insecticide is to be mixed with a solution contains 50%... (answered by richwmiller)
A chemist needs to mix a solution containing 30% insecticede with a solution containing... (answered by ptaylor)
A solution containing 30% insecticide is to be mixed with a solution of 50% insecticide... (answered by solver91311)
a solution containing 30% insecticide is to be mixed with solution containing 50%... (answered by checkley71)
I can't seem to find the solution to this problem. I would appreciate some guidance.... (answered by scott8148)