Hi

A planes flies south at 192mph. Two hours later another plane leaves at 960mph

Let x and (x-2)represent times traveled respectively

 D = rt (Distance traveled the same for both planes)

  192x = 960(x-2)

   1920 = 768 x

     x = 2.5 hrs , time traveled by slower plane.

Second plane will pass the first plane in 1/2 hr OR 30min.



CHECKING our Answer***

192*2.5 = 480mi = 960*(1/2) 

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