# SOLUTION: how do I solve by addition. the second equation of the system has me stumped. How do I elimated one? 5x-7y=2 3x=4y

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 Question 408312: how do I solve by addition. the second equation of the system has me stumped. How do I elimated one? 5x-7y=2 3x=4yAnswer by algebrahouse.com(1079)   (Show Source): You can put this solution on YOUR website!"how do I solve by addition. the second equation of the system has me stumped. How do I elimate one?" 5x - 7y = 2 3x = 4y-------->3x - 4y = 0 {subtracted 4y from both sides in 2nd equation} 5x - 7y = 2-------> -15x + 21y = -6 {multiplied top equation by -3} 3x - 4y = 0-------> 15x - 20y = 0 {multiplied bottom equation by 5} -15x + 21y = -6 15x - 20y = 0 -------------- y = -6 {added two new equations together and eliminated x} 5x - 7y = 2 {top original equation} 5x - 7(-6) = 2 {substituted -6, in for y, into top original equation} 5x + 42 = 2 {multiplied -7 by -6} 5x = -40 {subtracted 42 from both sides} x = -8 {divided both sides by 5} x = -8 and y = -6 www.algebrahouse.com