SOLUTION: the perimeter of a rectangle is 86 inches. The length exceeds the width by 9 inches. Find the length and the width? Where do I start?
Algebra.Com
Question 396465: the perimeter of a rectangle is 86 inches. The length exceeds the width by 9 inches. Find the length and the width? Where do I start?
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
2x+2(x+9)=86
2x+2x+18=86
4x=68
x=17 width
x+9=26 length
RELATED QUESTIONS
If the length of a rectangle exceeds the width by 9 inches and the perimeter is 86... (answered by ewatrrr)
perimeter of a rectangle is 112 inches the length exceeds the width by 4 inches find the... (answered by rfer)
THE PERIMETER OF A RECTANGLE IS 102 INCHES. THE LENGTH EXCEEDS THE WIDTH BY 9 INCHES.... (answered by rfer,MathLover1)
The perimeter of a rectangle is 230 inches. The length exceeds the width by 47 inches.... (answered by rdamanik)
The perimeter of a rectangle is 94 inches. The length exceeds the width by 5 inches.... (answered by Jstrasner)
The perimeter of a rectangle is 104 inches. The length exceeds the width by 14 inches.
(answered by tm.hodgson)
The length of a rectangle is 7 inches more than three times the width. The perimeter is... (answered by praseenakos@yahoo.com)
The perimeter of a rectangle is 36 inches. the length exceeds the width by 4 inches. what (answered by vksarvepalli)
The perimeter of a rectangle is 108 inches. The length exceeds the width by 8 inches.... (answered by oscargut)