SOLUTION: I need to write an equation of the line containing the given points and parallel to the given line. Express answer in y=mx+b forn (-9,6); 2x=3y+8 The equation of the line is y=

Question 389511: I need to write an equation of the line containing the given points and parallel to the given line. Express answer in y=mx+b forn
(-9,6); 2x=3y+8 The equation of the line is y=

Thank you
Found 3 solutions by mananth, haileytucki, Alan3354:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
I need to write an equation of the line containing the given points and parallel to the given line. Express answer in y=mx+b forn
(-9,6); 2x=3y+8 The equation of the line is y=

2x=3y+8
re write in the form y = mx +b
3y=2x-8
/3
y =(2x/3)-(8/3)
slope = m = 2/3
...
The slope of the required line will be the same since the line is parallel.
y= mx + b
(-9,6) the point & slope = 2/3
Find b by plugging thses values
6=(2/3)*-9+b
6=-6+b
b=12
..
slope = 2/3, b =12
The equation will be y = (2x/3)+12
...

m.ananth@hotmail.ca

Answer by haileytucki(390)   (Show Source): You can put this solution on YOUR website!
(-9,6)_2x=3y+8
Since y is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
3y+8=2x
Since 8 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 8 from both sides.
3y=-8+2x
Move all terms not containing y to the right-hand side of the equation.
3y=2x-8
Divide each term in the equation by 3.
(3y)/(3)=(2x)/(3)-(8)/(3)
Simplify the left-hand side of the equation by canceling the common factors.
y=(2x)/(3)-(8)/(3)
To find the slope and y intercept, use the y=mx+b formula where m=slope and b is the y intercept.
y=mx+b
Using the y=mx+b formula, m=(2)/(3).
m=(2)/(3)
The negative reciprocal of I is 0.
mperp=-(3)/(2)
Find the equation of the perpendicular line using the point-slope formula.
(-9,6)_m=-(3)/(2)
Find the value of b using the formula for the equation of a line.
y=mx+b
Substitute the value of m into the equation.
y=(-(3)/(2))*x+b
Substitute the value of x into the equation.
y=(-(3)/(2))*(-9)+b
Substitute the value of y into the equation.
(6)=(-(3)/(2))*(-9)+b
Since b is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
(-(3)/(2))*(-9)+b=(6)
Multiply (-(3)/(2)) by (-9) to get (-(3)/(2))(-9).
(-(3)/(2))(-9)+b=(6)
Remove the parentheses around the expression 6.
(-(3)/(2))(-9)+b=6
Multiply -(3)/(2) by -9 to get (27)/(2).
((27)/(2))+b=6
Reorder the polynomial (27)/(2)+b alphabetically from left to right, starting with the highest order term.
b+(27)/(2)=6
Find the value of b.
b=-(15)/(2)
Now that the values of m(slope) and b(y-intercept) are known, substitute them into y=mx+b to find the equation of the line.
y=-(3x)/(2)-(15)/(2)
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A line and a point example.
Write in standard form the eqation of a line that satisfies the given conditions. Perpendicular to 9x+3y=36, through (1,2)
-----------------
Find the slope of the line. Do that by putting the equation in slope-intercept form, y = mx + b. That means solve for y.
9x+3y = 36
3y= - 9x + 36
y = -3x + 12
The slope, m = -3
------------------
The slope of lines parallel is the same.
The slope of lines perpendicular is the negative inverse, m = +1/3
----------------
Use y = mx + b and the point (1,2) to find b.
2 = (1/3)*1 + b
b = 5/3
The equation is y = (1/3)x + 5/3 (slope-intercept form)
x - 3y = -5 (standard form)
------------------------
For further assistance, or to check your work, email me via the thank you note, or at Moral Loophole@aol.com
RELATED QUESTIONS
Hello! Write an equation of the line containing the given point and parallel to the... (answered by jim_thompson5910)
I need help! please help! write an equation of the line containing the given point and... (answered by Mathtut)
I need help with 6 problems, I have been trying to figure them out for 2 days now and... (answered by mananth)
1. find a equation of the line containing the given pair of points. (-5, -2) and (-3,-1). (answered by Alan3354)
Write an equation of the line containing the given point and parallel to the line.... (answered by ewatrrr)
Write an equation of the line containing the given point and parallel to the given point... (answered by nerdybill)
Write an equation of the line containing the given point and parallel to the given.... (answered by nyc_function)
write an equation of the line containing the given pointand parallel to the given line.... (answered by Maths68)
i need to write an equation of the line containing the given point and parallel to given... (answered by dabanfield)