Hi,         

the standard slope-intercept form for an equation of a line: y = mx + b  

where m is the slope and b the y-intercept.  

Line perpendicular to 2x + 7y = -49

2x + 7y = -49

      y = -(2/7)x - 7  slope is (-2/7)

Line perpendicular will have a slope = 7/2  (negative reciprocal)

New Line y = (7/2)x + b

     y = (7/2)x + b  using order pair pt(-7,-5) to solve for b

     -5 = 7/2)*-7 + b

     -100/2 - 49/2 = b

          -149/2 = b

     y = (7/2)x -149/2



    

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