SOLUTION: 4x+2y=2 -3x-y=-3

Algebra.Com
Question 386720: 4x+2y=2
-3x-y=-3

Answer by gwendolyn(128)   (Show Source): You can put this solution on YOUR website!
We have two equations and two variables, which means that we can probably solve this problem.
First, we will find y in terms of x. We will use the first equation to determine this.
4x+2y=2
We can subtract 4x from both sides:
2y=2-4x
And then divide both sides of the equation by two:
y=1-2x
Since we now have y in terms of x, we can substitute this into our second equation.
-3x-y=-3
-3x-(1-2x)=-3
Then, we can distribute the minus sign
-3x-1+2x=-3
-x-1=-3
Next, we can add 1 to both sides of the equation.
-x=-2
Finally, we divide both sides by negative one to isolate x.
x=2
Now that we have x's value, we can find y's value.
The first thing that we determined is:
y=1-2x
We can substitute in the value of x to this equation.
y=1-2x

y=1-4
y=-3
Therefore, we now have the values of both variables.
x=2
y=-3

RELATED QUESTIONS

Solve each system of equations: 2x= y+12 3x+2y= -3 What I did: (2x=y+12)2... (answered by TimothyLamb,Alan3354)
(4x)(2y)-(3x)(-y)= (answered by stanbon)
(4x-y)(3x+2y) (answered by checkley77)
4x-2y+3x-y (answered by rfer)
3x+2y=11... (answered by Fombitz)
4x+2y=2... (answered by TimothyLamb)
(4x^2 y)(3x^3 y^-1)=? (answered by Fombitz)
solve the system using your choice of method: 3x^2-2y^2=1... (answered by orca)
Solve the ff. turn them to y form 1/3x=y+2 3x-2y+8=0 4x-10y=0 3/4x+2y=8... (answered by checkley77)