# SOLUTION: suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?

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 Question 377513: suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?Found 2 solutions by mananth, ewatrrr:Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50? ... ... .. x=16,y=32 plug the value ... ... 32=4k /4 k=32/4 k=8 ... x=50, k= 8 y =56.56 ... m.ananth@hotmail.ca Answer by ewatrrr(10682)   (Show Source): You can put this solution on YOUR website! ``` Hi *Note: When Quantities vary directly,they are related by the relationship: In general: k being the constant of proportionality. y varies directly as the square root of x y=32 when x=16 32 = k*4 8 = k What is y when x=50 ```