SOLUTION: suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?

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Question 377513: suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?
Found 2 solutions by mananth, ewatrrr:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
suppose that y varies directly as the sqaure root of x, and that y=32 when x=16. What is y when x=50?
...

...

..
x=16,y=32
plug the value
...

...
32=4k
/4
k=32/4
k=8
...

x=50, k= 8

y =56.56
...
m.ananth@hotmail.ca

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
*Note: When Quantities vary directly,they are related by the relationship:
In general: k being the constant of proportionality.
y varies directly as the square root of x

y=32 when x=16
32 = k*4
8 = k
What is y when x=50


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