# SOLUTION: how do you solve this system by substitution then how the solution would be graph? thanks. y=x^3+x^2+x y=-3x

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 Question 374629: how do you solve this system by substitution then how the solution would be graph? thanks. y=x^3+x^2+x y=-3xAnswer by edjones(7569)   (Show Source): You can put this solution on YOUR website!y=x^3+x^2+x y=-3x . x^3+x^2+x=-3x x^3+x^2+4x=0 x(x^2+x+4)=0 x=0 . x^2+x+4=0 x^2+x =-4 x^2+x+ 1/4=-4+ 1/4 Complting the square. (x + 1/2)^2= -15/4 x + 1/2 = +-sqrt(-15)/2 x=-1/2 +- sqrt(15)i /2 x=(-1+sqrt(15)i)/2, x=(-1-sqrt(15)i)/2, x=0 . Ed