SOLUTION: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have? I can not figure out the

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Question 364485: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have?
I can not figure out the two equations.
I know that one is Dx + Ny = 95

Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Alex has dimes and nickels.
The total count is .
Each dime is worth 10 and each nickel is worth 5.
Total value equation:

1.
.
.
Total coin count equation:

2.
Substitute eq. 2 into eq. 1,



Then from eq. 2,



Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi,
Let x represent the number of dimes.
question statets the total coins then is (2x + 1)
The number of nickels is total coins - the number of dimes = [(2x+1) - x ]
Note: there are 5 cents in a nickel and 10 cents in a dime.
5[(2x+1) - x ] + 10x = 95 cents
simplify and slove for x
5[x + 1] + 10x = 95
5x + 5 + 10x = 95
15x = 90
x = 6, the number of dimes
number of nickles is [(2*6 + 1) - 6] = 7 nickels
checking our answer
5*7 + 6*10 = 35 cents + 60 cents = 95 cents
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