SOLUTION: [1,1] [0,3]
2x+y=3
Algebra.Com
Question 33800: [1,1] [0,3]
2x+y=3
Answer by fanism(39) (Show Source): You can put this solution on YOUR website!
the equation is:
x2-x1/y2-y1 = x-x1/y-y1
in your case,
x1, y1 = [1,1]
x2, y2 = [0,3]
therefore:
0-1/3-1 = x-1/y-1
-1/2 = x-1/y-1
-y+1=2x-2
0=2x+y-3
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