SOLUTION: t-2(3-2t)=2t+9 3t-6-2t^2+4t=2t+9 7t-6-2t^2=2t+9 5t-6-2t^2=9 5t-2t^2=15 -2t^2+5t-15=0 I believe I have it right to this point, but I can not remember how to simplify when it i

Question 337931: t-2(3-2t)=2t+9
3t-6-2t^2+4t=2t+9
7t-6-2t^2=2t+9
5t-6-2t^2=9
5t-2t^2=15
-2t^2+5t-15=0
I believe I have it right to this point, but I can not remember how to simplify when it is squared.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
-2t^2+5t-15=0 This is correct. Well done!
This is a quadratic equation. The quadratic equation gives no real numbers as answers.
If you are familiar with imaginary numbers the answer is:
t=5/4 + sqrt(95)/4 * i, t=5/4 - sqrt(95)/4 * i (See below)
.
Ed
.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -95 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -95 is + or - .

The solution is

Here's your graph:

RELATED QUESTIONS
t-2(3-2t)=2t+9 (answered by edjones)

(-.5t) + 2 = (.2t) + .8 t =... (answered by rfer)

2t^2-5t+2=0 (answered by mananth)

-2t^2*2t^3 (answered by chibisan)

Subtract (7 + t − 5t^2 + 2t^3) − (1 + 2t − 4t^2 + 5t^3) (answered by mananth)

Factor: 2t^2 + 5t -... (answered by scott8148)

Simplify.... (answered by Fombitz)

i have tried to answer this question and i have came up with three different answers.... (answered by Fombitz)

4t+5-2t=5t+6 (answered by stanbon)