# SOLUTION: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the mar

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the mar      Log On

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 Click here to see ALL problems on Linear-systems Question 336180: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber? Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber? ------------------- Robber DATA: rate = 12 mph ; time = x hrs ; distance = 12x miles -------------- Marshall DATA: rate = 16 mph ; time = x-(1/6) hr distance = 16(x-(1/6)) miles ---- Equation: distance = distance 12x = 16(x-(1/6)) 12x = 16x-(16/6) -4x = -(16/6) x = 2/3 hr ---- x-(1/6) = (4/6)-(1/6) = 1/2 hr (time needed for Marshall to catch robber) ============== Cheers, Stan H.