SOLUTION: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the mar

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the mar      Log On

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Question 336180: After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber?

Answer by stanbon(57387) About Me  (Show Source):
You can put this solution on YOUR website!
After robbing a bank in Dodge City, a robber gallops off at 12 mi/h. 10 minutes later, the marshall leaves to pursue the robber at 16 mi/h. How long (in hours) does it take the marshall to catch up to the robber?
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Robber DATA:
rate = 12 mph ; time = x hrs ; distance = 12x miles
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Marshall DATA:
rate = 16 mph ; time = x-(1/6) hr distance = 16(x-(1/6)) miles
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Equation:
distance = distance
12x = 16(x-(1/6))
12x = 16x-(16/6)
-4x = -(16/6)
x = 2/3 hr
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x-(1/6) = (4/6)-(1/6) = 1/2 hr (time needed for Marshall to catch robber)
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Cheers,
Stan H.