SOLUTION: I am having some trouble with this one. Solve the system of equations. Let z be the parameter. x+2y+3z=11 2x-y+z=2

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Question 332612: I am having some trouble with this one.
Solve the system of equations. Let z be the parameter.
x+2y+3z=11
2x-y+z=2

Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Solve the system of equations. Let z be the parameter.



Get the constants and parameter variable terms on the right



Eliminate y by multiplying the second equation through by 2:




Add corresponding terms:



Divide through by 5:





Substitute in 










Divide through by 2:





So the solution is (x,y) = (3-z,4-z)

Edwin

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