SOLUTION: Solve the system of equations:
y = x^2 - 4^x + 4 and y = -x^2 + 6x - 8
Algebra.Com
Question 330858: Solve the system of equations:
y = x^2 - 4^x + 4 and y = -x^2 + 6x - 8
Found 2 solutions by privani, Fombitz:
Answer by privani(34) (Show Source): You can put this solution on YOUR website!
Assuming Q1 is: ,
using equation rule: ,
y = (x-2)(x-2)
Q2:
y=(-x+4)(x-2)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Two solutions:
.
.
.
.
.
.
Now use either equation to solve for y.
,:(2,0)
,:(3,1)
.
.
.
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