SOLUTION: a+b+c=100
a+10b+50c=500
Algebra.Com
Question 31599: a+b+c=100
a+10b+50c=500
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
a=60 b=39 c=1 60+39+1=100 and
60+10*39+1*50=500 or 60+390+50=500 or 500=500
RELATED QUESTIONS
Solve the linear equations:
A + B + C = 0
4A - 10B = 3
-10B + 5C =... (answered by Fombitz)
a^2 + 2ab - 80b^2
A. (a - 10)(a + 8b)
B. (a - 10b)(a - 8b)
C. (a + 10b)(a - 8b)
(answered by ewatrrr)
a2 + 2ab – 80b2
A.
(a – 10)(a + 8b)
B.
(a – 10b)(a – 8b)
C.
(answered by ewatrrr)
If a+b+c=12 and 5a+10b+20c=175 WHAT is the value of a, b and... (answered by ikleyn)
9a+10b+12c=398
6a+4b+4c=164
1a+2b+1c=58
what is the value of... (answered by Alan3354)
If 1/(a - b) = 10, then a =
A) b+10
B) b+ (1/10)
C) b - (1/10)
D) (1 - 10b) /... (answered by Fombitz)
a^2-ab+10a-10b
______________
a+10
(answered by mukhopadhyay)
Let a and b be distinct real numbers for which
a/b + (a+10b)/(b+10a) = 2
Find... (answered by CubeyThePenguin,ikleyn)
HELP!!!!
9a+10b+12c=398
6a+4b+4c=164
1a+2b+1c=58
Solve for a,b,c and show... (answered by ankor@dixie-net.com)